Question

2. Find P(0), p(1) and p(2) for each of the following polynomials,
1) p(x)=x^2-x+1
2) p(y) =2+ y + 2y^2-y^3

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Answer 1

Answer:

1) P(0)= 1

P(1)= 1

P(2)= 3

2) P(0)= 2

P(1)= 6

P(2)= 12

Step-by-step explanation:

1)p(0)= 0^2-0+1=0-0+1=1

p(1)= 1^2-1+1= 1-1+1=1

p(2)=2^2-2+1=4-2+1=3

2) p(0)=2+0+2*0^2-0^3=2+0+0-0=2

p(1)=2+1+2*1^2-1^3=2+1+4-1=6

p(2)=2+2+2*2^2-2^3=2+2+16-8=12