Question

2. Find p(0), p(1) and p(2) for each of the following polynomials:


(iv) p(x) = (x - 1)(x+1)​

Answer 1

Answer:

p(0)

p(0)= 0-1 × 0+1

= 0^2 - 1^2

= 1

p 1 = 1-1×1+1

1^2-1^2

=0

p 2 = 2-1×2+1

=2^2- 1^2

= 4-1

=3