Question

2. Find p(0), p(1) and p(2) for each of the following polynomials p(x) = x square - 3x +2

Answer 1

Answer:

SO CONCEPT IS ZEROES OF POLYNOMIAL AND FOUR FUNDAMENTAL ARITHMETIC OPERATIONS , i.e. , ADDITION , SUBTRACTION , MULTIPLICATION , DIVISION.

Step-by-step explanation:

SO ,

1) IF P(0) ,

THEN ,

${x}^{2} - 3x + 2$

=

BY SUBSTITUTING x = 0 , we get ,

${(0)}^{2} - 3(0) + 2$

=

$0 - 3 \times 0 + 2$

=

$0 - 0 + 2$

=

$2$

SO IF P(0) THEN SOLUTION IS 2.

2) IF P(1) , THEN ,

${x}^{2} - 3x + 2$

=

BY SUBSTITUTING x = 1 , we get ,

${(1)}^{2} - 3(1) + 2$

=

$1 - 3 \times 1 + 2$

=

$1 - 3 + 2$

= BY SIMPLIFYING ,

$- 2 + 2$

=

$0$

SO , IF P(1) , THEN SOLUTION IS 0.

3) IF P(2) , THEN ,

${x}^{2} - 3x + 2$

= BY SUBSTITUTING THE VALUE OF x = 2 , we get ,

${(2)}^{2} - 3(2) + 2$

=

$4 - 3 \times 2 + 2$

=

$4 - 6 + 2$

=

$- 2 + 2$

=

$0$

SO , IF P(2) , THEN SOLUTION IS 0.

IF P(0) , THEN SOLUTION IS 2.

IF P(1) , THEN SOLUTION IS 0.

IF P(2) , THEN SOLUTION IS 0.

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