Question

2. Find p(0), p(1) and p(2) for each of the following polynomials:
(1) P(y) = y2-y+1
(iii) p(x)= x
(ii) p(t) = 2 +t+2t -
(iv) p(x)=(x - 1)(x + 1)​

Answer 1

Answer:

1.

p(0)=1

p(1)=1

0(2)=3

(iii)

p(0)=0

p(1)=1

p(2)=2

(ii)

p(0)=2

p(1)=5

p(2)=8

(iv)

p(0)=-1

p(1)=0

p(2)=3

I hope this answer may help you

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Answer 2

Step-by-step explanation:

All problems are solved and attached with this.