Question

2. Find p(0),p(1) and p(2) for each of the following polynomials:
(1) P() = y2 - y + 1 (ii) p(1) = 2 + 1 +212 --
(iii) p(x) = x
(iv) p(x) = (x - 1) (x + 1)​

Answer 1

Answer:

1)p(0)=1

p(1)=1

p(2)=3