2. Find p(0), p(1) and p(2) for each of the following polynomials:
(1) P(y) = y2-y + 1 (ü) p(t) = 2 + t + 2t2 - 43
(iii) p(x)= x
(iv) p(x)=(x - 1) (x + 1)
Answers
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ANSWER:-
I)p(y)=y^2-y+1
sol:- p(0)=o^2-0+1
=0-0+1=1
p(1)=1^2-1+1
=1-1+1
=0+1=1
p(2)=2^2-2+1
=4-2+1
=2+1=3
II)p(t)=2+t+2t^2-43
sol:- p(0)=2+0+2(0)^2-43
=2+0-43
= 2-43
=-41
p(2)=2+2+2(1)^2-43
=4+2(4)-43
=4+8-43
=12-43
=-31
p(1)=2+1+2(1)^2-43
=3+2-43
=5-43
=-38
III)p(0)=0
p(1)=1
p(2)=2
lV)p(0)=(0-1)(0+1)
=(-1)(1)=-1
p(1)=(1-1)(1+1)
=(0)(2)=0
p(2)=(2-1)(2+1)
=(1)(3)
=(3)
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