Question

2. Find p(0), p(1) and p(2)

(ii) p(t)=2+1+2t-t​

Answer 1

Step-by-step explanation:

p(0) = 2+1+0-0

= 3

p(1) = 2+1+2-1

= 4

p(2) = 2+1+4-2

= 5

Answer 2

p(t) = 2+1+2t-t

p(t) = 2+1+2t-tin first situation

p(0)= 2+1+2(0)-0

p(0)=2+1+0-0

p(0)=3

in second situation

p(1)=2+1+2(1)-1

p(1)=2+1+2-1

p(1)=4

in third situation

p(2)=2+1+2(2)-2

p(2) = 2+1+4-2

p(2)=5

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