Question

2. Find p(0),p(l) and p(2) for each of the following polynomials:
p(y)=y2-y+1​

Answer 1

Answer:

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Answer 2

Step-by-step explanation:

p( 0 ) = 0*2-0+1

= 1

p(1)=

$1 {}^{2} - 1 + 1 \\ 1 - 1 + 1 \\ = 1$

p(2)=

${2}^{2} - 2 + 1 \\ = 4 - 2 + 1 \\ = 3$

Hope ,it helpful for you