Question

2) Find p(1), p(2) for the following polynomial p(y) = y 2
– y + 1

Answer 1

P(y) =y2-y+1

p(y) =1

1*1-1+1=

1-1+1=0

p(y) =y2-y+1

p(y) =2

2*2-2+1

4-2+1

=3