Question

2. Find p(O),p(1) and p(2) for each of the following polynomials.
i p(x) = x2 - x +1
(i) p(y) = 2 + y + 2y2 - y3
(ii) p(z)=z?
(iv) p(t) = (1 - 1) (t+1)
(v) p(x) = x² – 3x + 2​

Answer 1

Step-by-step explanation:

i.P(0)=0X2-x+1

Ans=0-x+1

p(1)=1X2-x+1

Ans2-x+1

p(2)=2X2-x+2

Ans=4-x+2

ii. p(0)=2+0+2X0X2-0X3

4X0X2-0X3

Ans=0

p(1)=2+1+2X1X2-1X3

3+4-3

7-3

Ans=42

p(2)=2+2+2X2X2-2X3

4+8-6

Ans=6

iii. p(0)=0

Ans =0

p(1)=1

Ans =1

p(2)=2

Ans =2

iv. P(0)=(1-1)(0+1)

0X1

Ans=0

p(1)=(1-1)(1+1)

0X2

Ans=0

p(2)=(1-1)(2+1)

0X3

Ans=0

v. p(0)=0²-3X0+2

0-0+2

Ans =2

p(1)=1²-3X1+2

1-3+2

-2+2

Ans-4

P(2)=2²-3X2+2

4-3X2+2

2+2

Ans=4