Question

2. Find po),p(1) and p(2) for each of the following polynomials:
p(y)=y^2-y+1​

Answer 1

Answer:

sorry buddy I need some points

Answer 2

Answer:

p(y)=y^2-y+1​

So,

p(0) = 0²-0+1 = 1

p(1) = 1²-1+1 = 1

p(2) = 2²-2+1 = 3

Please mark my answer as BRAINLIEST...