2) Find slope of line perpendicular to the line 2x+5y-3=0
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Answered by
1
Slope of this eqn is = -b / a
-5 / 2
slope of a line perpendicular to this would be
2 / 5
m1 x m2 = -1 (perpendicular)
-5 / 2 x m2 = -1
m2 = 2 /5
Hope this Helps :)
Answered by
0
Answer:
7
Step-by-step explanation:
Step 1. 2x+5y-3 is 0
x + y = 0 + 3 5/2
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