Question

2
Find the 10 term of an AP: root 2, 3 root 2 , 5root 2 7 root 2

Answer 1

Given A.P ⟶ √2,  3√2,  5√2,  7√2

Here,

• First term = a = √2
• Common difference = d = 3√2 - √2 = 2√2

We need to find the 10th term of the A.P

General Term of an A.P

  ➤  aₙ = a + (n - 1)d

Applying this formula,

   aₙ = a + (n - 1)d

➥ a₁₀ = √2 + (10 - 1) (2√2)

⇒ a₁₀ = √2 + (9) (2√2)

⇒ a₁₀ = √2 + 18√2

⇒ a₁₀ = 19√2

∴ The 10th term of the A.P = 19√2

KNOW MORE:

• Sum of n terms can be given by the following formula:

Sₙ = n ÷ 2 [2a + (n - 1)d]

• When we know the first term and last term, the below formula can be used:

Sₙ = n ÷ 2 [a + aₙ]

Answer 2

Answer:

root 19

is answer of these questions