Question

2) Find the 10th term of the A.P 1,3,5
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Answer 1

Step-by-step explanation:

A1=1

A2=3

A3=5

D=2

formula: a+(n-1)d

1+(10-1)2

1+9×2

1+18

10th term= 19

Answer 2

The correct answer is 19.

Given: Arithmetic progression =  1,3,5...

To Find: Tenth term of arithmetic progression.

Solution:

Arithmetic progression =  1,3,5...

Common difference = Difference of two consecutive terms

Common difference = Second term - first term

Common difference(d) = 3 - 1 = 2

First term = a = 1

Formula of nth term = $T_{n}$ = a + (n-1)d

$T_{10}=1+(10-1)2$

= 19

Hence, the tenth term of AP is 19.

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