Question

2. Find the 34term of an A.P.4,9,14, ......​

Answer 1

Answer:

t34=169

Step-by-step explanation:

a=4;d=9-4=5;n=34

tn=a+(n-1)d

t34=4+(34-1)5

t34=4+(33*5)

t34=4+165

t34=169

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Answer 2

Here,

$\sf a = 4$

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$\sf d = a_{2} - a_{1}$

$\sf : \implies d = 9 - 4$

$\sf : \implies d = 5$

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Now, we know that

$\sf a_{n} = a + (n-1)d$

$\sf : \implies a_{34} = a + (34-1)d$

$\sf : \implies a_{34} = a + 33d$

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Now, put values of a and d

$\sf : \implies a_{34} = 4 + 33 × 5$

$\sf : \implies a_{34} = 4 + 165$

$\sf : \implies a_{34} = 169$

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$\sf \therefore \: 34^{th} \: term \: of \: A.P. \: 4,9,14,... \: is \: 169$