Question

2. Find the Amount and Compound interest if Principal = Rs. 4000, Rate = 10
p.c.p.a and Duration = 2 years.​

Answer 1

Answer:

Given :

• Principal = ₹4000
• Rate = 10 p.c.p.a.
• Time = 2 years

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To Find :

• Amount
• Compound Interest

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Solution :

We know that,

$\mapsto \boxed{\bf \orange{Amount = Principal \times \bigg ( 1 + \dfrac{r}{100} \bigg)^{t}}}$

$\mapsto \sf Amount = 4000 \times \bigg ( 1 + \dfrac{5}{100} \bigg)^{3}$

$\mapsto \sf Amount = 4000 \times \bigg( \dfrac{105}{100} \bigg )^{3}$

$\mapsto \sf Amount = 4000 \times \dfrac{105}{100} \times \dfrac{105}{100} \times \dfrac{105}{100}$

$\mapsto \sf Amount = 4000 \times \dfrac{105}{100} \times \dfrac{105}{100} \times \dfrac{105}{100}$

$\mapsto \sf Amount = 4630.5$

$\implies\boxed{\bf { Amount = Rs. \: 4630.5 }}$

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We know that,

Compound Interest = Amount - Principal

Compound Interest = 4630.5 - 4000

Compound Interest = 630.5

$\implies\boxed{\bf { Compound \: Interest = Rs. \: 630.5} }$

Answer 2

Step-by-step explanation:

Principal=4000

R=10

D=2

A=?

C.I=?

A=P+(r/100)N

=4000+(10/100)2

4000×10/100×10/100

4×110×110

10

A=4,840

C.I=A-P

=4840-4000

=840