2. Find the amount and compound interest on 10240 for 3 years at 12 1 per annum compound
annually.
10
100
annum,
3. The present population of a town is 176400. If it increases at the rate of 5% per annum, what
be its population after 2 years?
4. Amit started a shop by investing 250000, He gained 4% during first year, 5% during second
and 10% during 3rd year. What will be his capital amount after these 3 years?
[Hint : Capital amount after 3 years = 50000 * 1+
5. A mango tree of height 125 cm was planted 3 years ago. If it increases at the rate of 20
what is its present height?
6. Two years ago, the population of a town was 10000. During first year, it increased at th
of 5% per annum and during second year, it increased at the rate of 6% per annum. Wha
present population?
7. Mahesh borrowed 716000 at 75% per annum simple interest. On the same day, he lent it to
at the same rate but compounded annually. What does he gain at the end of 2 years?
8. A machine is purchased for 625000. Its value depreciates at the rate of 8% per annur
will be its value after 2 years?
9. A car is purchased for 348000. Its value depreciates at 10% per annum during the first
at 20% per annum during the second year. What will be its value after 2 years?
Answers
Answer
Heya❣❣
Here is your answer mate!
2. Given:
Present value= 10240
50%
Interest rate= 12 % % per annum 25/2%
Time=3 years
To find the amount we have the formula,
Amount (A) = P (1+(R/100))
Where Is present value, is rate of
interest, n is time in years.
Now substituting the values in above
formula we get,
A = 10240 (1 + (25/2)/100)3
A= 10240 (1+1/8)3
A = 10240 (9/8)
A = 31250 x 729/512 20 x 729
>A = 14580
. Compound interest = A -P
= 1458010240 =4340
3. Total population in 2 years is 194481.
Total population 2 years ago is 160000.
4. Amit 25000 X12 mesthu
Maths
69
4.0 (1 ratings
Vinay 230000
x 9monuna
25 X 12 290 x9
20
18
10 : 9 Profit = 19000
Amit a share 10x19000 10+9)
10 x 19000 1000
dmit's shore=T10000
5. Answer:
216cm
Step-by-step explanation:
use formula of compounds interest
A = p(1+r/100)'n
present height = 125(1+20/100)^3
H=1256/56/5x6/5
H= 216cm
6. Answer:
47%
II
Spotify Premium
Two years ago population =10000 After one year its population will be at the
rate of 5%
=105/100*10000=10500
Current year population at the rate 6%=
106/100 10500=11130
The present population 1130
7. Given that Mahesh borrowed 16000 rupees at 71/2% per annum Simple interest.
P = 16000
R=71/2
= 15/2%
T= 2
We know that SI = PRT/100
= 16000 152/2
= 16000 15/100
= 2400.
100
We know that A = P+I
= 16000 + 2400
= 18400.
Given that he lent it to Gagan at the same rate.
Given R = 15/2.
n = 2 years.
P = 16000
We know that A = P(1 + r/100)^n
= 16000(1 + 15/200)^2
= 16000215 /200)2
= 1600043 /40)^2
= 16000 1849/1600
= 10 * 1849
= 18490.
Therefore the gain = 1849018400
= 90.
8. Given:- Principal =Rs 625000
rate = 8% per annum time=2 yrs.
So, Amount = P(1-1/100)^(since the value is
depreciated)
= 62500018 /100r2
= 62500092 /100*92/100) = Rs 529000.
9. Its value depreciates at 10% per annum during the first year and at 20% per
annum during the second year. What will
be its value after 2 years? Initial value of the car, P Rs 348000 Rate of p 100 x 1-q 100 = Rs.
I answered all your questions..