Question

(2. Find the amount and the compound interest on Rs 4000 at 10% p.a. for 2/2 years.​

Answer 1

Answer:

1082

Step-by-step explanation:

Principal(P) = Rs 4000

Rate of Interest(r ) = 10%

Time = 2.5 years Here first we take n = 2 years.

A = P( 1 + r /100)n Where A = Amount and n = number of years

A = 4000 (11/10)2

A = 4000 ( 121 / 100 )

A = Rs 4840

The Amount after two years = Rs 4840 Now Principal = Rs 4840

Simple interest for last ½ year is = PRT/100 = (4840 × 10 × 1 / 2) / 100 = Rs.242

Amount after 2 ½ year = Rs 4840 + Rs 242 = Rs 5082

C.I = A - P

C.I = Rs 5082 - Rs 4000 = Rs1082

∴ The compound interest is Rs 1082.