2. Find the amount of water displaced by a solid spherical ball of diameter
(1) 28 cm
(i) 0.21 m
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- 11498.67 cm^3 approx
- 0.0049 m^3
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Solutions :
1) Diameter of the solid spherical bowl , d= 28 cm
Radius, r= d/2 = 28/2 cm =14 cm
Volume of the water displaced by the ball
= 4/3 π r^3 = 4/3 ×22/7×14×14×14 cm^3
= 11498.6667 cm^3 = 11498.67 cm^3
=> 11498.67 cm^3 Approx ✔︎✔︎
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2) Diameter of the ball d= 0.21 m
Radius r= d/2 = 0.21 m
Volume of the water displaced by the ball
= 4/3πr^3 =4/3×22/7×0.21/2×0.21/2×0.21/2 m^3
=> 0.0049 m^3 ✔︎✔︎
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