Math, asked by sunitagajbhiye7070, 9 months ago

2) Find the angle of depression from the top of 15 m high tower of an object lying at a point 15 m away from the base of the tower.​

Answers

Answered by kushalchauhan07
5

Answer:

Height of the tower = 15m

distance between object and tower = 15m

let height be p and distance between object and tower be b.

tanθ = \frac{p}{b}

θ = \frac{15}{15}  = 1

so \: tan45º = 1

angle of depression = 45º

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Answered by sweetysinghal7109
0

Hey mate!

Here is ur answer

Given that,

the height of the tower is 15m.

the distance b/w object nd the tower is 15m.

So, tan theta = perpendicular/base

= 15/15 = 1

thus, the angle of depression will be 45°.

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