2) Find the angle of depression from the top of 15 m high tower of an object lying at a point 15 m away from the base of the tower.
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Answer:
Height of the tower = 15m
distance between object and tower = 15m
let height be p and distance between object and tower be b.
angle of depression = 45º
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Hey mate!
Here is ur answer❤
Given that,
the height of the tower is 15m.
the distance b/w object nd the tower is 15m.
So, tan theta = perpendicular/base
= 15/15 = 1
thus, the angle of depression will be 45°.
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