Question

2) Find the area and perimeter of a rhombus whose diagonols measure 28cm and 96 cm.​

Answer 1

Step-by-step explanation:

let the quadrilateral ABCD be the given rhombus

by the property of rhombus

diagonals are perpendicular to each other

let the point O where both diagonals meet each other

Now

in triangle ABO

angle B=90°

by pythagoras theorem

AB^2=AO^2+OB^2

=14^2+48^2

=196+2304

AB^2=2500

AB=50

Now,

by the property of rhombus

all sides are cougrent

AB=BC=CD=AD=50cm

I HOPE YOU GOT THE ANSWER