Question

2. Find the area bounded between y=x2 and y=x in the first quadrant
and find the volume of revolution of this area about the x-axis​

Answer 1

Answer:

V=πb∫a[f(x)]2dx. The cross section perpendicular to the axis of revolution has the form of a disk of radius R=f(x). Similarly, we can find the volume of the solid when the region is bounded by the curve x=f(y) and the y−axis between y=c and y=d, and is rotated about the y−axis.