Math, asked by chandrakalabagati, 1 month ago

2.
Find the area enclosed

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Answers

Answered by harshsandhu1617
1

Step-by-step explanation:

ABCD is a square

area if square= side × side

=4×4

=16cm²

ABC is a triangle

area of triangle= 1/2×base×height

base = 4 cm. height=6-4=2cm

area= 1/2×4×2

=4cm²

total area= 16+4=20cm²

Answered by riyabansal0407
0

Step-by-step explanation:

Area of square=4×side

=4×4cm²

=16cm²

Length of AC=Length of DE=4cm (all sides of square are equal)

Construction=Let point intersecting AC be F

Total length=6cm

CD=4cm

BF=6cm-4cm

=2cm

Area of triangle ABC=1/2×base×height

=1/2×AC×BF

=1/2×4×2

=4cm²

Area of enclosed figure=Area of square+Area of triangle-AC (AC is common)

=16cm²+4cm²-4cm

=16cm²

Pls mark me as brainliest

Hope it helps u dude

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