Question

2. Find the area of a quadrant of a circle whose circumference is 22 cm.​

Answer 1

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Answer......

Answer 2

$\huge\underline{\mathbb\blue{SOLUTION!!...}}$

circumference of the circle = 22cm

2πr = 22

$2 \times \frac{22}{7} \times r = 22$

$\frac{22}{7} \times r = 11$

$22 \times r = 77$

$r = \frac{77}{22}$

$r = 3.5cm$

$\green{\underline\textbf{</strong><strong>area</strong><strong> </strong><strong>of</strong><strong> </strong><strong>quadra</strong><strong>nt</strong><strong> </strong><strong>=</strong><strong> </strong><strong>}</strong><strong>}$

$\frac{1}{4} \times \pi \: {r}^{2}$

$\frac{1}{4} \times \frac{22}{7} \times 3.5</strong><strong>/</strong><strong>2</strong><strong> \times 3.5</strong><strong>/</strong><strong>2</strong><strong>$

$\</strong><strong>r</strong><strong>e</strong><strong>d</strong><strong>{\underline\textbf{</strong><strong>area</strong><strong> </strong><strong>of</strong><strong> </strong><strong>quad</strong><strong>rant</strong><strong> </strong><strong>=</strong><strong> </strong><strong>2</strong><strong>.</strong><strong>4</strong><strong>0</strong><strong>6</strong><strong>}</strong><strong>}</strong><strong>$cm²

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