2. Find the area of a quadrilateral PQRS in which angle QPS = angle SQR = 90. PQ=12 cm,PS = 9 cm, QR = 8 cm and SR = 17 cm (Hint: PQRS has two parts)
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Answer:
In ∆PQS
PQ^2+PS^2=QS^2
QS=15cm
By applying herons formula in triangle PQS AND triangle QRS
we get,
area of PQS =54 cm^2
area of QRS = 60cm^2
area of PQRS= area of PQS +area of QRS
area of PQRS=114 cm^2
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