Question

2. Find the area of an isosceles triangle ABC in which BC= 8 cm and AB = AC = 5 cm. If CE perpendicular to AB, find CE.​

Answer 1

Given :-

AB = AC = 5cm

BC = AE + EB = 8 cm

AE = 4cm

CE perpendicular to AB

Find :-

height (CE) = ?

Solution :-

by using Pythagoras theorem

(AC)^2 = (AE)^2 + (CE) ^2

( 5 )^2 = ( 4 )^2 + ( CE) ^2

25 = 16 + ( CE) ^2

(CE) ^2 = 25 - 16 = 9 cm

CE = 3cm

Area of an isosceles triangle

= 1/2 * base * height

= 1/2 * 8 * 3

= 12cm^2