Question

2. Find the area of circle whose perimeter is
(i) 28 cm​

Answer 1

Answer:

A=πr2

p=2πr

Solving forA

A=p2

4π=282

4·π≈62.38874

Answer 2

Step-by-step explanation:

Given :-

Given :-Diameter = 28 cm.

Given :-Diameter = 28 cm.Radius = D/2 = 14 cm.

Given :-Diameter = 28 cm.Radius = D/2 = 14 cm.Area of circle = πr²

Given :-Diameter = 28 cm.Radius = D/2 = 14 cm.Area of circle = πr²\begin{gathered}= \frac{22}{7} \times 14 \times 14 \\ = 22 \times 2 \times 14 \\ = 44 \times 14 \\ = 616 {cm}^{2}\end{gathered}

Given :-Diameter = 28 cm.Radius = D/2 = 14 cm.Area of circle = πr²\begin{gathered}= \frac{22}{7} \times 14 \times 14 \\ = 22 \times 2 \times 14 \\ = 44 \times 14 \\ = 616 {cm}^{2}\end{gathered} =

Given :-Diameter = 28 cm.Radius = D/2 = 14 cm.Area of circle = πr²\begin{gathered}= \frac{22}{7} \times 14 \times 14 \\ = 22 \times 2 \times 14 \\ = 44 \times 14 \\ = 616 {cm}^{2}\end{gathered} = 7

Given :-Diameter = 28 cm.Radius = D/2 = 14 cm.Area of circle = πr²\begin{gathered}= \frac{22}{7} \times 14 \times 14 \\ = 22 \times 2 \times 14 \\ = 44 \times 14 \\ = 616 {cm}^{2}\end{gathered} = 722

Given :-Diameter = 28 cm.Radius = D/2 = 14 cm.Area of circle = πr²\begin{gathered}= \frac{22}{7} \times 14 \times 14 \\ = 22 \times 2 \times 14 \\ = 44 \times 14 \\ = 616 {cm}^{2}\end{gathered} = 722

Given :-Diameter = 28 cm.Radius = D/2 = 14 cm.Area of circle = πr²\begin{gathered}= \frac{22}{7} \times 14 \times 14 \\ = 22 \times 2 \times 14 \\ = 44 \times 14 \\ = 616 {cm}^{2}\end{gathered} = 722 ×14×14

Given :-Diameter = 28 cm.Radius = D/2 = 14 cm.Area of circle = πr²\begin{gathered}= \frac{22}{7} \times 14 \times 14 \\ = 22 \times 2 \times 14 \\ = 44 \times 14 \\ = 616 {cm}^{2}\end{gathered} = 722 ×14×14=22×2×14

Given :-Diameter = 28 cm.Radius = D/2 = 14 cm.Area of circle = πr²\begin{gathered}= \frac{22}{7} \times 14 \times 14 \\ = 22 \times 2 \times 14 \\ = 44 \times 14 \\ = 616 {cm}^{2}\end{gathered} = 722 ×14×14=22×2×14=44×14

Given :-Diameter = 28 cm.Radius = D/2 = 14 cm.Area of circle = πr²\begin{gathered}= \frac{22}{7} \times 14 \times 14 \\ = 22 \times 2 \times 14 \\ = 44 \times 14 \\ = 616 {cm}^{2}\end{gathered} = 722 ×14×14=22×2×14=44×14=616cm

Given :-Diameter = 28 cm.Radius = D/2 = 14 cm.Area of circle = πr²\begin{gathered}= \frac{22}{7} \times 14 \times 14 \\ = 22 \times 2 \times 14 \\ = 44 \times 14 \\ = 616 {cm}^{2}\end{gathered} = 722 ×14×14=22×2×14=44×14=616cm 2

Given :-Diameter = 28 cm.Radius = D/2 = 14 cm.Area of circle = πr²\begin{gathered}= \frac{22}{7} \times 14 \times 14 \\ = 22 \times 2 \times 14 \\ = 44 \times 14 \\ = 616 {cm}^{2}\end{gathered} = 722 ×14×14=22×2×14=44×14=616cm 2

Given :-Diameter = 28 cm.Radius = D/2 = 14 cm.Area of circle = πr²\begin{gathered}= \frac{22}{7} \times 14 \times 14 \\ = 22 \times 2 \times 14 \\ = 44 \times 14 \\ = 616 {cm}^{2}\end{gathered} = 722 ×14×14=22×2×14=44×14=616cm 2

Given :-Diameter = 28 cm.Radius = D/2 = 14 cm.Area of circle = πr²\begin{gathered}= \frac{22}{7} \times 14 \times 14 \\ = 22 \times 2 \times 14 \\ = 44 \times 14 \\ = 616 {cm}^{2}\end{gathered} = 722 ×14×14=22×2×14=44×14=616cm 2

Given :-Diameter = 28 cm.Radius = D/2 = 14 cm.Area of circle = πr²\begin{gathered}= \frac{22}{7} \times 14 \times 14 \\ = 22 \times 2 \times 14 \\ = 44 \times 14 \\ = 616 {cm}^{2}\end{gathered} = 722 ×14×14=22×2×14=44×14=616cm 2 Hence the area of the given circle is 616 cm².