Question

2. Find the area of the following figures.​

Answer 1

Answer:

It is a regular hexagon which can be divided in 6 equilateral triangles.

It will be solved using Heron's formula .

Heron's formula =$\sqrt{s(s-a)(s-b)(s-c)}$   (where a,b,c are length of sides)

s = $\frac{a+b+c}{2} = \frac{6+6+6}{2} = \frac{18}{2} = 9$

Area of 1 equilateral triangle = $\sqrt{s(s-a)(s-b)(s-c)}$

                                                  =  $\sqrt{9(9-6)(9-6)(9-6)} = \sqrt{9*3*3*3} = \sqrt{243} = 15.588$$cm^{2}$

Are of whole figure = $6 * 15.588 = 93.528$$cm^{2}$

Area of Whole figure is 93.528 $cm^{2}$

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Answer 2

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