Question

2. Find the area of the following quadrilateral: 15 cm 28 cm D 9 cm A 40 cm -B 156. ​

Answer 1

Answer:

AreaΔABC=

2

1

×9×40cm

=180cm

2

In ΔABC

AC=

40

2

+9

2

cm

=41cm

In ΔADC

s=

2

41+15+28

=42 cm

Area ΔADC=

42(42−41)(42−18)(42−15)

cm

2

=126cm

2

Area of quadrilateral ABCD=(180+126)cm

2

=306cm

2

Answer 2

Answer:

Area ∆ ABC =

Step-by-step explanation:

2

1

×9×40cm= 180cm

2

In∆ ABC

AC=

40

2

+9

2

cm

=41 cm

In ∆ ADC

s=

2

41+15+28

= 42 cm

Area∆ADC=42(42-41)(42-18)(42-15)

CM

2=126cm

Area of quadrilateral ABCD=(180+ 126) cm

2

= 306cm

2