2. Find the area of the shaded region in the adjoining figure in which PQ = 24 CM
and OR 7 cm. (Take n = 3.14)
answer is 322.625m^2
(hint:calculate PR=PSsq +SRsq squareroot and now radius QR =1/2 PR
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Answer:
322.625cm²
Step-by-step explanation:
given,pq=24cm ,qr=7cm
area of rectangle= l×b =7×24=168cm²
Diameter =pr
pr² = ps²+sr²
pr²=7²+24²
pr² =49+576
pr²=625
pr=√625=√25×25=25 cm
radius,or=1/2 pr = 1/2×25=25/2=12.5 cm
therefore,area of circle= πr²
=3.14×12.5×12.5=490.625 cm²
Area of shaded region= area of circle - area of rectangle
=490.625-268 = 322.625 cm²
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