2) Find the area ofrectangle whose dimensions are 24cm and 25cm
3) Solve the following equation
5x-14=1
4) Constructa perpendicular bisector of line segment mn oflength 8cm
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1) area of rectangle = l × b
area = 24 × 25
Therefore, area of rectangle = 600 sq.m
2) 5x-14=1
5x= 1 +14
5x=15
x= 15 / 5
therefore , x = 5
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