Math, asked by dungrothprasanthi, 14 days ago

2. Find the average of first 6 consecutive even numbers
6
7
1
0​

Answers

Answered by shivikaur85
0

Answer:

2+4+6+8+10+12 = 42

=42/6

= 7

7 is the answer

Answered by pulakmath007
0

The average of first 6 consecutive even numbers is 7

Given :

The of first 6 consecutive even numbers

To find :

The average of first 6 consecutive even numbers is

  • 6

  • 7

  • 1

  • 0

Solution :

Step 1 of 3 :

Write down the given numbers

Here we are given first 6 consecutive even numbers

Now first 6 consecutive even numbers are 2 , 4 , 6 , 8 , 10 , 12

Step 2 of 3 :

Calculate Sum of the numbers

Here the given numbers are 2 , 4 , 6 , 8 , 10 , 12

Number of observations = 6

Sum of the numbers

= 2 + 4 + 6 + 8 + 10 + 12

= 42

Step 3 of 3 :

Calculate the average

The required average of first 6 consecutive even numbers

\displaystyle \sf{ =  \frac{Sum  \: of \:  the  \: observations}{Number \:  of \:  observations}   }

\displaystyle \sf{ =  \frac{42}{6}   }

\displaystyle \sf{ = 7}

Hence the correct option is 7

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