Question

2. Find the base of a right angle of area 42 cm² and height 6 ​

Answer 1

Answer:

Base=14

Step-by-step explanation:

Given:-area of triangle=42cm sq.

Height=6

Area of Right angled triangle=1/2*b*h

1/2×b×6=42

b=42×2/3

b=14

Answer 2

$\huge\mathtt\color{Orange}{Answer}$

Given that :-

Area of Right angled ∆ = 42cm²

Height = 6cm

To find :-

The Base of the ∆

Solution :-

Let , the Base be x cm :-

$Area\:of\:Right-Angled\:∆=\frac{1}{2}×Height×Base$

$Area\:of\:Right-Angled\:∆=\frac{1}{2}×6×x$

$Area\:of\:∆=3x$

$\frac{42}{3}=x$

$14cm=x$

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•°• Base of the Right -Angled ∆ =14cm