Question

2
Find the correct option for 36 gm C,H,Oc.
(A) 4.8 NA molecules of C,H,06 (B) 19.2 N, electrons
(C) 0.8 moles
(D) 0.6 gm molecules​

Answer 1

Answer:

C.) 0.8 moles.

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Answer 2

CORRECT QUESTION

Find the correct option for 36 gm C₆H₁₂O₆

(A) 4.8 Nₐ molecules of C₆H₁₂O₆

(B) 19.2 Nₐ electrons

(C) 0.8 moles

(D) 0.6 gm molecules of oxygen.

ANSWER

The correct option (B) 19.2 Nₐ electrons

GIVEN

Weight of C₆H₁₂O₆ = 36 grams

TO FIND

The correct option

SOLUTION

(1) 4.8 Nₐ molecules of C₆H₁₂O₆

Given weight of C₆H₁₂O₆ = 36 grams

molecular mass of C₆H₁₂O₆ = 180 grams

Moles of C₆H₁₂O₆ = 36/180 = 0.2 moles

According to Stochiometry,

Number of molecules in 1 mole of C₆H₁₂O₆ = Nₐ

(Nₐ = 6.022 × 10²³ )

So,

Number of molecules in 0.2 moles of C₆H₁₂O₆ = 0.2Nₐ

Hence, Option (A) is incorrect .

(B) 19.2Nₐ electrons

Number of electrons per mole of C₆H₁₂O₆

number of Electrons in 6 atoms of Carbon = 6 × 6 = 36

Number of electrons in 12 atoms of Hydrogen = 12×1 = 12

Number of electrons in 6 atoms of Oxygen = 8×6 = 48

Total electrons in 1 molecule of Glucose = 36+12+48= 96

Number of electrons in 0.2Nₐ molecules of Glucose = 96 × 0.2 × Nₐ = 19.2 Nₐ

Hence, Option (B) is correct .

(c) 0.8 moles.

We have already calculated number of moles in 36 grams of C₆H₁₂O₆ as 0.2 moles.

Hence, Option (C) is incorrect.

(4) 0.6 gm molecules of Oxygen

We know that,

Gram molecule = 0.6 /16 = 0.037

Therefore, option (4) is not correct.

Hence, The correct option is (B) 19.2 Nₐ electrons

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