Question

2.
Find the current flowing through the following
32
M АЛ
3.ba
AM
62
AM
T2
32
-HHE
4.5 V​

Answer 1

Answer:

Since, resistors 1Ω and 3Ω are in series,

∴Req1=1+3=4Ω

Now, resistors 4Ω and 6Ω are in parallel,

∴Req2=4Ω∥6Ω=4+64×6=1024=2.4Ω

Now, 3.6Ω,2.4Ω and 3Ω are again series,

∴Req=3.6+2.4+3=9Ω

Now, the current flowing the electric current I

I=ReqV

⇒I=94.9=0.5Amp

⇒I=0.5Amp