Question

.
(2) Find the curved surface area of a cylinder of radius 14 cm and height 21 cm.
(3) A Conical solid block is exactly fitted inside the cubical box of side 'a' then the volume of
conical solid block is 4/3 na.” Is this statement true? Justify your answer.​

Answer 1

Answer:

CSA= 2pirh

2*22/7*14*21

2*22*2*21

88*21

1848cm2

Hp it hlps uuh ...

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Answer 2

Question:-

Find the curved surface area of a cylinder of radius 14 cm and height 21 cm.

Answer:-

→ Curved surface area = 1848 cm^{2}

To Find :-

→ Curved surface area of cylinder .

Formula used :-

$\boxed{ \text{curved \: surface \: area} \: = \bf{ 2 \pi \: r \: h \:} }$

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Step - by - step explanation :-

Given that,

• Radius of cylinder (r) = 14 cm

• Height of cylinder (h) = 21 cm

Solution :-

Now,

Using the given formula

• Curved surface area of cylinder is

$\implies \: \: \bf{ 2 \pi \: r \: h \: } \\ \\ \implies \: 2 \: \pi \: \times 14 \times 21 \\ \\ \because \: \boxed{\pi \: = \frac{22}{7} } \\ \\ \therefore \: \\ \\ \implies \: 2 \times \frac{22}{7} \times 14 \times 21 \\ \\ \implies \: 44 \times 42 \\ \\ \implies \: 1848 \: {(cm)}^{2}$

Therefore the curved surface area of cylinder is 1848 cm^{2} .

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