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Find the diagonal of a square whose side is 10 em.
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Answer:
d =√2a
10/√2=a
a=5√2cm
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let ABCD is the sqaure
AB=BC=CD=AD..=10.......,..... .............side of the sqaure
AC is the diogonal
Now in triangle ABC angle B=90
by Pythagoras theorem
AC^,=AB^+BC^
=10^+10^
=100+100
=200
√100×2
=10√2........... taking square root
The diagonal of square is 10√2
I hope understand you...
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