Question

2. Find the digit at the units place of the cubes
of each of the following numbers:
(i) 333
(ii) 516
(iii) 320
(iv) 122
(v) 535
(vi) 101
(vii) 249
(viii) 227
(ix) 234
(x) 108

Please do answer with the whole method and I will mark you as the brainliest !​

Answer 1

Answer:

(i) 64

\sqrt[3]{64}=\sqrt[3]{2\times2\times2\times2\times2\times2}

3

64

=

3

2×2×2×2×2×2

\sqrt[3]{64}=\ 2\times2

3

64

= 2×2

= 4

(ii) 512

\sqrt[3]{512}=\sqrt[3]{2\times2\times2\times2\times2\times2\times2\times2\times2}

3

512

=

3

2×2×2×2×2×2×2×2×2

= 2 x 2 x 2 = 8

(iii) 10648

\sqrt[3]{10648}=\sqrt[3]{2\times2\times2\times11\times11\times11}

3

10648

=

3

2×2×2×11×11×11

= 2 x 11

= 22

(iv) 27000

\sqrt[3]{27000}=\sqrt[3]{2\times2\times2\times3\times3\times3\times5\times5\times5}

3

27000

=

3

2×2×2×3×3×3×5×5×5

= 2 x 3 x 5

= 30

(v) 15625

\sqrt[3]{15625}=\sqrt[3]{5\times5\times5\times5\times5\times5}

3

15625

=

3

5×5×5×5×5×5

= 5 x 5

= 25

(vi) 13824

\sqrt[3]{13824}=\sqrt[3]{2\times2\times2\times2\times2\times2\times2\times2\times2\times3\times3\times3}

3

13824

=

3

2×2×2×2×2×2×2×2×2×3×3×3

2 x 2 x 2 x 3

= 24

(vii) 110592

\sqrt[3]{110592}=\sqrt[3]{2\times2\times2\times2\times2\times2\times2\times2\times2\times2\times2\times2\times3\times3\times3}

3

110592

=

3

2×2×2×2×2×2×2×2×2×2×2×2×3×3×3

= 2 x 2 x 2 x 2 x 3

= 48