Question

2. Find the equation of lines parallel to y-axis whose distances from it are respectively (a) -3 (b) (b) 5/7
(C) -a​

Answer 1

Answer:

Step-by-step explanation:

The given line can be written as 4x+3y−12=0....(1)

Thus using distance formula,

4=  

4  

2

+3  

2

 

​

 

∣4(0)+3(b)−12∣

​

 

⇒4=  

5

∣3b−12∣

​

 

⇒20=∣3b−12∣

⇒20=±(3b−12)

⇒20=(3b−12) or 20=−{3b−12}

⇒3b=20+12 or 3b=−20+12

⇒b=  

3

32

​

  or  b=−  

3

8

​

 

Thus, the required points are (0,  

3

32

​

)and(0,−  

3

8

​

).