2. Find the equation of the circle whose
centre lies on the X - axis and passing
through (-2, 3) and (4, 5).
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Given that the center lies on X axis. Let the coordinates of center of circle be (h,0)
The distance from center to points (−2,3) and (4,5) is equal
So we get (h+2)
2
+(0−3)
2
=(h−4)
2
+(0−5)
2
⇒12h=28
⇒h=
3
7
r
2
=(x−h)
2
+(y−k)
2
r
2
=(4−
3
7
)
2
+(5)
2
∴ The radius of circle is r=
25+
9
25
=
3
5
10
The equation of circle is (x−
3
7
)
2
+y
2
=
9
250
I hope this is helpful
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