Question

2. Find the equation of the line containing the points (2, -3) and (0, -3).​

Answer 1

Answer: This may help you

Step-by-step explanation:

First find the slope of the line with these points as

m=(y2-y1/x2-x1)

and then substitute m in the eqn. (y-y1)=m( x-x1)...

then you'll get the required line

here m=0

therefore, y-(-3)=0(x-0)

y+3=0 is the eqn....for the given points including line.

Answer 2

............hope it helps .....