2) Find the
equation
of the normal to the curve
x² = 4y passing through (1,2)
Answers
Answered by
0
Answer:
sorry I can't no
Step-by-step explanation:
sorry bro or sis
Answered by
1
Answer:
h^2=4k
−1/dy/dx=−2/h
equation of normal(y−k)=−2/h(x−h)
k=2+2/h(1−h)
h^2/4=2+2/h(1−h)
h=2
k=1
equation of line
(y-1)=-1(x-2)
x+y=3
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