2) Find the equation of the straight line passing through (-2, 3) and inclined at an angle of 45 with the x- axis
Answers
Answered by
34
Answer:
x - y + 5= 0
Step-by-step explanation:
Slope of the line(m) = tanα = tan45° = 1
A point on the line is (-2, 3) = (x₁ , y₁)
Hence the equation of the line is:
⇒ y - y₁ = m(x - x₁)
⇒ y - (3) = 1(x - (-2))
⇒ y - 3 = x + 2
⇒ x - y + 5 = 0
Required equation is x - y + 5 = 0
Answered by
154
⚘ Question :-
- Find the equation of the straight line passing through (-2, 3) and inclined at an angle of 45° with the x- axis.
⚘ Answer :-
- Required equation is x - y + 5 = 0.
✧ Explanation ✧
⚘ Given :-
- Straight line passing through (-2, 3)
- Inclined at an angle of 45° with the x- axis
⚘ To Find :-
- Equation of the straight line?
⚘ Solution :-
★ Finding slope of line ::
➨ Slope of line (m) = tanθ
➨ Slope of line (m) = tan45°
➨ Slope of line (m) = 1
Now,
★ Finding eqⁿ of the straight line ::
We know that,
Let,
- be y
- be x
We have,
- m = 1
- = y
- = 3
- = x
- = -2
By plugging all values in formula we get,
➨
➨
➨
➨
➨
➨
➨
➨
∴ Eqⁿ of straight line is x - y + 5 = 0.
⚘ Know More :-
Important Formulae:
- For finding distance between two points we use distance formula i.e,
- For finding a ratio in which line segment is divided by a point we use section formula i.e,
⚘ Learn More on Brainly :-
Question:
- If the slope of the line passing through the point (2,5) and (-4,k) is 3/2, then the value of k is
Answer:
- brainly.in/question/41369991
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