Question

2. Find the first four terms of the sequence whose nth term is an = = 2n²-6.​

Answer 1

Answer:

if n =1 then a= 2*1^2 -6= -4

if n= 2 then a= 2*2^2 -6=2

if n=3 then a= 2*3^2-6=12

if n=4 then a=2*4^2-6=26