Question

2) Find the gravitational force of attraction between to elephants, one of mass 1.00 x 10³ kg and the other of mass 8.00x10² kg when they are separated by 5.0m class 9 solution​

Answer 1

Answer:

21.12 × 10⁻⁷ N

Explanation:

Given:

Mass of Elephant = 1.00 × 10³ Kg

Mass of Another Elephant = 8.00 × 10²

Distance between them = 5.0 m.

Value of G = 6.7 × 10⁻¹¹

Let the mass of Elephant = M

And mass of Another Elephant = m

Let the Distance be = d

Force of Attraction Formula:

→ F = G × (M × m) / d²

Now, Substitute the Values according to formula:

→ F = 6.7 × 10⁻¹¹ (1 × 10³ × 8 × 10²) / 5²

→ F = 21.12 × 10⁻⁷ N

F = 21.12 × 10⁻⁷ N

Note : See the attachment for The Calculation!