Question

2) Find the greatest number which will divide 21, 39 and 48 so as to leave the remainder 3 in
each case​

Answer 1

Answer:

Here, we need to find differences between the given numbers. If two numbers give the same remainder when divided by some other number, then their difference must give a remainder of zero when divided by that number.

Our numbers here are 91−43=48,183−91=92,183−43=140

So we have the set of numbers {48,92,140} and we want to know the biggest number that divides all these numbers.

So,

48=2×2×2×3

92=2×2×23

140=2×2×5×7

The greatest common divisor of {48,92,140} is 4.

So, answer is 4.

Explanation:

Hope it helps you ☺️

Answer 2

Answer:

HCF of 21 39 48=4

Explanation:

hcf of 21 39 48=4