2. Find the H.C.F. of the following monomials.
(iv) 15a - 45a, 150a
Answers
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SOLUTION
TO DETERMINE
The H.C.F. of the following monomials.
(iv) 15a , - 45a , 150a
EVALUATION
Here the given monomial are
15a , - 45a, 150a
15a = 3 × 5 × a
-45 a = - 3 × 3 × 5 × a
150a = 2 × 3 × 5 × 5 × a
Hence the required HCF
= 3 × 5 × a
= 15a
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