Question

2. Find the HCF of the following:
a)
18. 54. 81
b)
51, 112, 49
c)
36, 72, 12
d)
30, 42, 112
e)
27, 63, 118
f)
36, 84, 630​

Answer 1

Answer:

(a) Factors of 18 = 2 x 3 x 3 (b) Factors of 30 = 2 x 3 x 5

Factors of 48 = 2 x 2 x 2 x 2 x 3 Factors of 42 = 2 x 3 x 7

H.C.F. (18, 48) = 2 x 3 = 6 H.C.F. (30, 42) = 2 x 3 = 6

(c) Factors of 18 = 2 x 3 x 3 (d) Factors of 27 = 3 x 3 x 3

Factors of 60 = 2 x 2 x 3 x 5 Factors of 63 = 3 x 3 x 7

H.C.F. (18, 60) = 2 x 3 = 6 H.C.F. (27, 63) = 3 x 3 = 9

(e) Factors of 36 = 2 x 2 x 3 x 3 (f) Factors of 34 = 2 x 17

Factors of 84 = 2 x 2 x 3 x 7 Factors of 102 = 2 x 3 x 17

H.C.F. (36, 84) = 2 x 2 x 3 = 12 H.C.F. (34, 102) = 2 x 17 = 34

(g) Factors of 70 = 2 x 5 x 7 (h) Factors of 91 = 7 x 13

Factors of 105 = 3 x 5 x 7 Factors of 112 = 2 x 2 x 2 x 2 x 7

Factors of 175 = 5 x 5 x 7 Factors of 49 = 7 x 7

H.C.F. = 5 x 7 = 35 H.C.F. = 1 x 7 = 7

(i) Factors of 18 = 2 x 3 x 3

(j) Factors of 12 = 2 x 2 x 3

Factors of 54 = 2 x 3 x 3 x 3 Factors of 45 = 3 x 3 x 5

Factors of 81 = 3 x 3 x 3 x 3 Factors of 75 = 3 x 5 x 5

H.C.F. = 3 x 3 = 9 H.C.F. = 1 x 3 = 3

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