2.
Find the HCF of the following numbers by prime factorisation method. 3
(a) 76, 28
(b) 24, 16, 36
(c) 38, 64, 82
Answers
Answered by
55
a) 76 = 2×2×19
28 = 2×2×7
HCF of 76 and 28 is 4
b) 24 = 2×2×2×3
16 = 2×2×2×2
36=2×2×3×3
HCF of 24 ,16 ,36 is 4
c) 38, 64, 82
38=2×19
64=2×2×2×2×2×2
82=2×41
HCF of 38, 64, 82 is 2
Answered by
1
Answer:
answer is
a= 532
b= 864
c= 49856
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