Question

2. Find the HCF of the following numbers by the prime factorisation method.
a. 28, 42, and 49​

Answer 1

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HCF of 28, 42, 49 is 7 the largest number which exactly divides all the numbers i.e. where the remainder is zero. Let us get into the working of this example.

Consider we have numbers 28, 42, 49 and we need to find the HCF of these numbers. To do so, we need to choose the largest integer first and then as per Euclid's Division Lemma a = bq + r where 0 ≤ r ≤ b

Highest common factor (HCF) of 28, 42, 49 is 7.

HCF(28, 42, 49) = 7

Answer 2

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28 = 2 * 2 * 7

42 = 2 * 3 * 7

49 = 7 * 7

THEREFORE HCF = 7

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